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 Friday 20th of September

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 Depdendent Variable

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 Dependent Variable

 Number of inequalities to solve: 23456789
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# The Ellipse

An ellipse is the set of points P in the plane such that the sum of the distances from P to two fixed points F1 and F 2 is a constant.
F1P + F 2P = k the points F1 & F 2 the foci.
Using the idea of the two stacked cones, the ellipse is made when an angled vertical cut is made

The important characteristics of the ellipse:

Example 1
Given 4x 2 + y 2 = 36 , find the equation of the ellipse and give the coordinates of the foci.
Solution:

## The foci

Given the equation, we see the major axis is along the y axis, and is centred at the origin.
This means the vertices are at (0, -6) & (0,6), with co- vertices at (-3,0) & (3,0).

 a 2 = b 2 + c 2 36 - 9 = c 2 27 = c 2 = c

Hence the foci are at (0,  )  and  (0, )
Ellipse are often not centered at the origin: Hence the possible ellipses are

Sketch , and label the foci
We can from the equation that the major axis is parallel to the x axis.
The length of the major axis is 2a, which is 10. the minor axis is 2b, which is 8.
The vertices are (h - a , k) & (h + a, k), which are going to give ( -6, 3) & (4, 3).
The co-vertices are (h, k - b) & ( h, k + b), which are going to give (-1, -1) & (-1, 7).
The foci are going to be (h - c, k) & ( h + c, k)
Where c is equal to

 a 2 = b 2 + c 2 c 2 = 25 - 16 c = 3

Hence the foci are ( -4, 3 ) & ( 2, 3 )
Write the equation of an ellipse in standard form given:
Â· The centre is at (2,-1).
Â· The major axis is 16 units and is parallel to the x axis.
Â· The minor axis is 4 units.
Solution:
The centre is at (2,-1), with h = 2 & k = -1.
If the length of the major axis is 16, and the major axis is 2a, then

16 = 2a

a = 8

The length of the minor axis is 2.
Since we know h, k, a ,b we can solve the equation.